Aspring with a force constant of 111nm is attached to the ceiling. when an unknown mass is attached it pulls the spring down 0.340meters to its equilibrium position. the mass is then pulled 9cm below its equilibrium position and oscillates back and forth. determine the period of oscillation (in seconds)?

T = 1.17 s

Explanation:

As we know that unknown mass is attached with a spring

then in the equilibrium position the force of gravity on the mass is balanced by the spring force on the block

so we have

now we have

here we know that

now we know that time period of the SHM is given as

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

a electromagnetic waves