What is the index of refraction of a material for which the wavelength of light is 0.6024 times its value in a vacuum? identify the likely substance

1.66 , This value corresponds to flint glass.

Explanation:

Refractive index is equal to velocity of the light 'c' in empty space divided by the velocity 'v' in the substance.

Or ,

n = c/v.

Also,

c = frequency × Wavelength

The formula can be written as:

n = λ / λn.

Where,

λn is the wavelength in the medium

λ is the wavelength in vaccum

Given that: λn = 0.6024 λ

So, n is:

n = λ / λn = λ / 0.6024 λ = 1.66

This value corresponds to flint glass.

when a device is used in a circuit in which the voltage is 81 v, the current flowing through the device is 3 a. what is the resistance of the device?

a. 27 ω

b. 40.5 a

c. 243 ω

d. 243 a

the correct answer is a. 27