Particles a, b of mass 3m, 2m respectively are attached to the ends of a light inextensible string passing over a smooth pulley. the system is held at rest, the string is taut and the parts of the string not in contact with the pulley are vertical. the system is then released. after b has travelled 5 m it hits and coalesces with a particle of mass 5m at rest. find the impulse in the string. find also the time taken from the impact until the system first comes momentarily to rest. [take g as 10 m/s? ].

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

come closer and become far apart and become steam/gas

the answer is 3.1 his answer is wrong mines is right