Apoint source of light illuminates an aperture 2.00 m away. a 15.0 cm -wide bright patch of light appears on a screen 2.00 m behind the aperture. how wide is the aperture?

wide is the aperture is 7.5 cm

Explanation:

Given data

aperture away =  2.00 m

wide bright = 15 cm = 0.15 m

screen behind the aperture =  2.00 m

to find out

How wide is the aperture

solution

we know here we have a triangle shape that height will be

2 + 2 = 4 m and base 0.15 m

so we now easy find w by triangle

w / 2 = 0.15 / 4

so w = 0.15 / 4 × 2

so w = 0.075 m

wide is the aperture is 7.5 cm

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.