An ac series circuit contains a resistor of 25 ohms, an inductor of 10.5 mh and a variable capacitor. if the frequency of the applied voltage is 190 hz, to what setting should the capacitor be set if resonance is achieved? a) 61.75μf b) 66.83 μf c) 29 μf d) 84μf e) 52.725 μf

B) 66.83 μF

Explanation:

R = resistance of the resistor = 25 ohm

L = inductance of the inductor = 10.5 mH = 0.0105 H

f = resonance frequency achieved = 190 Hz

C = Capacitance of the capacitor

For resonance to be possible

C = 66.83 x 10⁻⁶ F

C = 66.83 μF

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!