Two sources of light of wavelength 686 nm are separated by a horizontal distance x. they are 3 m from a vertical slit of width 0.5 mm. what is the least value of x for which the diffraction pattern of the sources can be resolved by rayleigh's criterion?

X = 5.48 mm

Explanation:

for single slit

By Rayleigh criterian

where d = slit width =0.5 mm

wavelength

therefore maximum of value of X can be  calculated from above

X = 5.48 mm

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