How much work is done to move 1 uc of charge from the negative terminal to the positive terminal of a 1.5v battery?

1.5 x 10⁻⁶ J

Explanation:

q = magnitude of charge on the charge = 1 x 10⁻⁶ C

ΔV = Potential difference between positive and negative terminals of battery = 1.5 Volts

W = Amount of work done to move the charge from negative terminal to the positive terminal

Work done is given as

W = q ΔV

W = (1 x 10⁻⁶) (1.5)

W = 1.5 x 10⁻⁶ J

the correct answer is b

b) 10 minutes

girls stopped for 10 minutes.