Abasketball player is running at 5.00 m/s directly toward the basket when he jumps into the air to dunk the ball. he maintains his horizontal velocity. what vertical velocity does he need to rise 0.750 m above the floor?

3.834 m/s

Explanation:

h = 0.750 m

vx = 5 m/s

Let the initial vertical velocity is vy.

Final vertical velocity is zero

use third equation of motion along y axis

v^2 = vy^2 - 2 x g x h

0 = vy^2 - 2 x 9.8 x 0.75

vy^2 = 14.7

vy = 3.834 m/s