Astudent and his lab partner create a single slit by carefully aligning two razor blades to a separation of 0.530 mm. when a helium–neon laser at 543 nm illuminates the slit, a diffraction pattern is observed on a screen 1.55 m beyond the slit. calculate the angle θdark to the first minimum in the diffraction pattern and the width of the central maximum.

angle = 0.058699 degree

width of central maximum  is 3.170566 × m

distance D =  1.55 m

wavelength w = 543 nm = 543× m

to find out

angle θ and width of the central maximum

solution

we know according to first condition first dark that mean

wavelength = dsinθ

so put value and find θ

543× = 0.530× ×sinθ

sinθ  =  543× / 0.530×

sinθ   =  1.02452 × [tex]10^{-3}

θ = 0.058699 degree

and

we can say

tanθ = y/D

here y is width of central maximum Y = 2y

put all value we get  y

so y = D tanθ

y = 1.55 (tan0.0586)

y = 1.58528 × [tex]10^{-3} m =

so Y = 2 ( 1.58528 × [tex]10^{-3} )

so width of central maximum  is 3.170566 × [tex]10^{-3} )  m

answer; (d) spontaneous processes are characterized by the overall conversion of order to disorder;

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.