Agolf club strikes a 0.045-kg golf ball in order to launch it from the tee. for simplicity, assume that the average net force applied to the ball acts parallel to the ball’s motion, has a magnitude of 6800 n, and is in contact with the ball for a distance of 0.010 m. with what speed does the ball leave the club?

speed of ball is 54.97 m/s

Explanation:

given data

mass of ball m = 0.045 kg

distance s = 0.010 m

net force F  = 6800 N

to find out

what speed does the ball leave the club

solution

we consider W = change in kinetic energy

so F×s = 1/2 mv²

we will find v  from here

v =

put all value

v =  

v = 54.9747 m/s

speed of ball is 54.97 m/s

a

explanation:

no diagram was provided, but i'm guessing it's the one i've attached to my answer.

here, a mechanical force turns the rod.   this generates an electric current in the coil, which powers the bulb.

it is a negative acceleration