This time particle a starts from rest and accelerates to the right at 65.5 cm/s
2
. particle
b starts 349 cm down the track and moves at
a constant velocity of 44 cm/s to the left.
when will they meet?
answer in units of s.

t = 4 s

Explanation:

As we know that the particle A starts from Rest with constant acceleration

So the distance moved by the particle in given time "t"

Now we know that B moves with constant speed so in the same time B will move to another distance

now we know that B is already 349 cm down the track

so if A and B will meet after time "t"

then in that case

on solving above kinematics equation we have

ill do it for 100, also this isnt 80 its 40

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