Acircular loop of diameter 10 cm, carrying a current of 0.20 a, is placed inside a magnetic field b⃗ =0.30 tk^. the normal to the loop is parallel to a unit vector n^=−0.60i^−0.80j^. calculate the magnitude of the torque on the loop due to the magnetic field.

The magnitude of the torque on the loop due to the magnetic field is .

Explanation:

Given that,

Diameter = 10 cm

Current = 0.20 A

Magnetic field = 0.30 T

Unit vector

We need to calculate the torque on the loop

Using formula of torque

Where, N = number of turns

A = area

I = current

B = magnetic field

Put the value into the formula

Hence, The magnitude of the torque on the loop due to the magnetic field is .

newton's first law of motion

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

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explanation: