What is the period of revolution for a comet with aphelion at 5 au and perihelion at the orbit of earth?

Given:

For the comet:

Aphelion = 5 AU

Solution:

For the Comet:

Perihelion = 1 AU

So, the length of the major axis, a = Aphelion + Perihelion = 1 + 5 = 6 AU

the length of the semi major axis = radius, R = = 3 AU

According to Kepler's third law of planetary motion:

                                           (1)

where,

T = Time period of rervolution for comet

Using eqn (1):

T = 5.196 ≈ 5.2 years

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get the total number of pieces of fruit and divide it by 4 to get the average. the result is the answer to the problem. 14 total number of fruits and there are 4 members. 14 divided by 4 is equals to 3.5.