Light traveling in a vacuum has a wavelength of 550nm when it enters a pool of water (n = 1.33). what would the wavelength of the light be in the water? (a) 336nm (b) 414nm (c) 550nm (d) 732nm

b) 414nm

Explanation:

let λ1 be the wavelenght of light in a vacuum and λ2 be the wavelength of light in water.

the relationship between the refractive index  wavelenghts in a vacuum and in water is given by:

n = λ1/λ2

λ2 = λ1/n

    = (550)/(1.33)

   = 413.53 nm

   ≈ 414nm

Therefore the wavelength of light in water is 414mn.

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