Physics, 07.08.2019 04:10 tiffcarina69

Two students are pushing identical crates across a frictionless floor. the crates are initially at rest. bing applies a horizontal force of 23 n to his crate. bob, who is shorter than bing, pushes on his crate at an angle of 33° below the horizontal, also with a force of 23 n. find the ratio of the masses of the two crates if bing’s crate is moving at twice the speed of bob’s crate after they have traveled a distance of 33.5 m across the floor? (20 pts)

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Answer from: cody4976

$\frac{m_1}{m_2} = 0.298$

Explanation:

As we know that both the crates are moving at different speed after moving 33.5 m

speed of bling crate = 2 (speed of bob crate)

now we know that

Bling apply force horizontal so the acceleration of his crate is given as

$a_1 = \frac{23}{m_1}$

now force of Bob is at 33 degree with the horizontal

so the acceleration of crate of Bob is given as

$a_2 = \frac{23 cos33}{m_2}$

now we know that work done by Bling and bob on their crate is equal to the kinetic energy of the crate

so for Bling's and Bob'scrate we can say

$F. d = \frac{1}{2}m v^2$

now the ratio of the work done of two is given as

$\frac{W_1}{W_2} = \frac{0.5 m_1 v_1^2}{0.5 m_2 v_2^2}$

$\frac{23 d}{23 d cos33} = \frac{m_1 (2v)^2}{m_2(v^2)}$

$\frac{1}{cos33} = \frac{4 m_1}{m_2}$

$\frac{m_1}{m_2} = 0.298$

Answer from: Quest

answer and explanation;

composition refers to both the types of minerals within a rock and the overall chemical makeup of the rock while texture refers to the size and arrangement of the minerals or grains that make up a rock. both composition and texture can be used to classify rocks, such as igneous rocks. texture describes how the rock became solid or crystallized from liquid, melted rock. composition of a rock describes the minerals that make up a particular rock.

Answer from: Quest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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