Daniel takes his two dogs, pauli the pointer and newton the newfoundland, out to a field and lets them loose to exercise. both dogs sprint away in different directions while daniel stands still. from daniel's point of view, newton runs due north at 3.40 m/s, but from pauli's point of view, newton appears to be moving at 1.10 m/s due east. what must pauli's velocity relative to daniel be for this to be true? express your answer in terms of the ‑ and ‑components if north is the + ‑direction and east is the + ‑direction.

The velocity of Pauli relative Daniel in y-direction is -3.4 m/s and in x-direction is 1.1 m/s.

The given parameters;

The sketch of the Newton's velocity is presented as follows;

                                                ↑ 3.4 m/s North

                                                ↑

                                                ↑---------→ 1.1 m/s East

For the above velocity of Newton to be true, the velocity of Pauli relative to Daniel is calculated as follows;

Thus, the velocity of Pauli relative Daniel in y-direction is -3.4 m/s and in x-direction is 1.1 m/s.

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Explanation:

3.4 m/s due North, -1.1 m/s due East

your answer is c! hope this : )

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