If the 78.0 kg astronaut were in a spacecraft 6r from the center of the earth, what would the astronaut's weight be on earth? 764.4 n760 n764 n in the spacecraft? 21.24 n21 n21.3 n

(a) 764.4 N

The weight of the astronaut on Earth is given by:

where

m is the astronaut's mass

g is the acceleration due to gravity

Here we have

m = 78.0 kg

g = 9.8 m/s^2 at the Earth's surface

So the weight of the astronaut is

(b) 21.1 N

The spacecraft is located at a distance of

from the center of Earth.

The acceleration due to gravity at a generic distance r from the Earth's center is

where G is the gravitational constant and M is the Earth's mass.

We know that at a distance of r = R (at the Earth's surface) the value of g is 9.8 m/s^2, so we can write:

(1)

the acceleration due to gravity at r=6R instead will be

And substituting (1) into this formula,

So the weight of the astronaut at the spacecratf location is

a=d/t

a="triangle"v/t

explanation:

a = acceleration