J8. over several cycles, a refrigerator compressor does work on the refrigerant. this work is equivalent to a constant pressure of 413 × 105 pa compressing a circular piston with a radius of 0,.019 m a distance of 25.0 m. if the change in the refrigerant's internal energy is 0 j after each cycle, how much heat will the refrigerant remove from within the refrigerator?

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

Your answer is 1.5 hope i  

This is the answer: body 1 + engine 2

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