Suppose you exert a force of 180 n tangential to a 0.280-m-radius 75.0-kg grindstone (a solid disk). what is the angular acceleration assuming negligible opposing friction

Explanation:

It is given that,

Force on grindstone, F = 180 N

Radius of grindstone, r = 0.28 m

Mass of grindstone, m = 75 kg

We need to find the angular acceleration of the grindstone. In rotational motion, the relation between the torque and angular acceleration is given by :

I is the moment of inertia of solid disk,

is the torque exerted,

So, the angular acceleration of the disk is . Hence, this is the required solution.

it takes about 30 days for it to break down

more than, less

less than, more