Speakers a and b are vibrating in phase. they are directly facing each other, are 7.80 m apart, and are each playing a 73.0 - hz tone. the speed of sound is 343 m/s. one the line between the speakers there are three points where constructive interference occurs. what are the distances of these three points from speaker a?

The distances of these three points from speaker A are 6.25 m, 3.9 m and 1.55 m.

Explanation:

Given that,

Distance = 7.80 m

Frequency f = 73.0 Hz

Speed of sound = 343 m/s

We need to calculate the wavelength

Using formula of wavelength

Put the value into the formula

Let the distance from speaker A is x.

The distance from speaker B is (7.80-x).

Difference between the distance must be a whole number of wavelength.

For first point,

Put the value of wavelength

For second point,

Put the value of wavelength

For third point,

Put the value of wavelength

Hence, The distances of these three points from speaker A are 6.25 m, 3.9 m and 1.55 m.

c

explanation:

f is prop to m1xm2 double m1 double force