Aforce of 140 140 newtons is required to hold a spring that has been stretched from its natural length of 40 cm to a length of 60 cm. find the work done in stretching the spring from 60 cm to 65 cm. first, setup an integral and find a a, b b, and f ( x ) f(x) which would compute the amount of work done.

The work done in stretching the spring is 0.875 J.

Explanation:

Given that,

Force = 140 N

Natural length = 60-40 = 20 cm

Stretch length of the spring = 65-60 = 5 cm

We need to calculate the spring constant

Using formula of Hooke's law

We need to calculate the work done

On integration

Hence, The work done in stretching the spring is 0.875 J.

5 w for 1hr = 5x60x60 joules=300x60=3000x6=18,000j as total energy conversion. efficiency of bulb needed for radiant to thermal within 18000