A28 g ball of clay traveling east at 3.5 m/s collides with a 35 g ball of clay traveling north at 2.8 m/s.
what is the movement direction of the resulting 63 g blob of clay?
what is the speed of the resulting 63 g blob of clay?

45 deg north of east

2.3 m/s

Explanation:

Assuming east as directed along positive x-axis and north as directed along positive y-axis

m₁ = mass of clay ball traveling east = 28 g

v₁ = velocity of ball traveling east = 3.5 i m/s

m₂ = mass of clay ball traveling north  = 35 g

v₂ = velocity of ball traveling north = 2.8 j m/s

m = mass of the combination of two balls after collision = 63 g

v = velocity of the combination after collision

Using conservation of momentum

m₁ v₁ + m₂ v₂ = m v

(28) (3.5 i) + (35) (2.8 j ) = 63 v

98 i + 98 j  = 63 v

1.6 i + 1.6 j = v

Direction :

θ = tan⁻¹(1.6/1.6)

θ = 45 deg north of east

Speed is given as

|v| = sqrt((1.6)² + (1.6)²)

|v| = 2.3 m/s

568.98

explanation:

its math

ill do it for 100, also this isnt 80 its 40