Bees develop a positive charge as they fly through the air. when a bee lands on a flower, charge is transferred, and an opposite charge is induced in the earth below the flower. the flower and the ground together make a capacitor; a typical value is 0.60 pf. if a flower is charged to 30 v relative to the ground, a bee can reliably detect the added charge and then avoids the flower in favor of flowers that have not been recently visited. approximately how much charge must a bee transfer to the flower to create a 30 v potential difference?

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

i believe the answer would be:

d. violin, clarinet, french horn, and tuba

scattering of light by tiny particles in air to produce the colors we see on sky, is dependent on the following factors:

(i) wavelength of light

(ii) size of the scattering particle  

(iii) distance traveled by light through the atmosphere.

according to rayleigh's law of scattering, the amount of scattering is inversely proportional to the fourth power of its wavelength. shorter the wavelength, greater is its scattering. hence violet/blue light is scattered more than red.

sun's light is a composite light ( visible light) with wavelengths in the range 400 nm (violet) to 700 nm (red). as sunlight passes through our atmosphere, the molecules of air scatter light according to their wavelengths. during sunrise and sunset, the sun's position is below the horizon. hence light from the sun travels a greater distance in the atmosphere when compared to its position a noon.

as sunlight enters the earth's atmosphere, blue light is scattered away and at the end of its journey in the sky, only red and orange wavelengths remain in the beam.

hence at sunrise and sunset, the sky appears reddish orange.