Acharged capacitor is connected to an ideal inductor. at time t = 0, the charge on the capacitor is equal to 6.00 μc. at time t = 2.00 ms the charge on the capacitor is zero for the first time. what is the amplitude of the current at that same instant?

Explanation:

= Maximum charge stored by capacitor = 6 μC = 6 x 10⁻⁶ C

 = time taken for charge on the capacitor to become zero = 2 ms = 2 x 10⁻³ s

Time period is given as

Angular frequency is given as

=785 rad/s

Charge at any time is given as

Taking derivative both side relative to "t"

Amplitude of the current is given as

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

answer and explanation;