Acertain metal having a work function of 5.4 ev is illuminated with light of frequency 2.7 x 1015hz. determine the stopping potential (in v) that is required to stop the most energetic ejected electrons. your answer should be a number with two decimal places, do not include unit.

5.79 Volts

Explanation:

W = work function of the metal = 5.4 eV = 5.4 x 1.6 x 10⁻¹⁹ J = 8.64 x 10⁻¹⁹ J

f = frequency of light = 2.7 x 10¹⁵ Hz

V₀ = stopping potential for the electron = ?

q = magnitude of charge on electron = 1.6 x 10⁻¹⁹ C

Using conservation of energy

e V₀  = hf - W

(1.6 x 10⁻¹⁹) V₀  = (6.63 x 10⁻³⁴) (2.7 x 10¹⁵) - 8.64 x 10⁻¹⁹

V₀  = 5.79 Volts

no sign of dia of fuel cell

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.