Consider a point 0.5 m above the midpoint of the two charges. as you can verify by removing one of the positive charges, the electric field due to only one of the positive charges is about 18 v/m. what is the magnitude of the total electric field due to both charges at this location

the magnitude of the total electric field is 25 V/m

Explanation:

Given data

point above = 0.5 m

charges = 18 V/m

to find out

the magnitude of the total electric field

solution

the magnitude of the total electric field is 25 V/m because number is less than    the twice magnitude of field by every charge and  the horizontal component in electric field by every charge cancel out and vertical component in field added together

answer: point c: b. 1/2 potential, 1/2 kinetic, point a: 3/4 of its potential energy, point d or b: 3/4 potential, 1/4 kinetic

explanation: i cant explain. it's difficult to explain.

overcharge is the right answer system