Two manned satellites approach one another at a relative velocity of =0.210v=0.210 m/s, intending to dock. the first has a mass of =4.00×103m1=4.00×103 kg and the second a mass of =7.50×103m2=7.50×103 kg. if the two satellites collide elastically rather than dock, what is their final relative velocity?

Explanation:

It is given that,

Relative velocity of two manned satellites, v = 0.210 m/s

Mass of first satellite,

Mass of other satellite,

The two satellites collide elastically rather than dock, we need to find their final velocities. Let v' is the final velocity. We know that in an elastic collision, both momentum and kinetic energy remains constant.

Also, the relative velocity of approach between two satellites before collision is same as the relative velocity of separation after collision. So, their final relative velocity is 0.210 m/s but in opposite direction.

answer: the correct answer id option(d).

explanation:

snell's law refraction:

the angle of refraction =

the angle of incidence =

refractive index of air = = 1

refractive index of glycerol = 1.47

from the given options, the most closest answer to 63.72° is 65° of option (d).

more than, less

less than, more