The fixed hydraulic cylinder c imparts a constant upward velocity v = 2.2 m/s to the collar b, which slips freely on rod oa. determine the resulting angular velocity ωoa when point b has a displacement s = 220 mm, and the fixed distance d = 510 mm. the angular velocity is positive if counterclockwise, negative if clockwise.

so angular velocity is 7.13128 sec−1

Explanation:

velocity v = 2.2 m/s

displacement s = 220 mm = 0.220 m

distance d = 510 mm = 0.510 m

to find out

angular velocity

solution

we know that

angular velocity will be velocity ( v)  / (displacement²  +  distance²)   1

now put all these value in equation 1 and we get angular velocity i.e.

angular velocity =  velocity ( v)  / (displacement²  +  distance²)

angular velocity = 2.2  / (0.22²  +  0.51²)

angular velocity = 2.2 / 0.3085

angular velocity = 7.13128

so angular velocity is 7.13128 sec−1

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