A350-n, uniform, 1.50-m bar is suspended horizontally by two vertical cables at each end. cable a can support a maximum tension of 500.0 n without breaking, and cable b can support up to 400.0 n. you want to place a small weight on this bar. part a what is the heaviest weight you can put on the bar without breaking either cable

The heaviest weight that can be put on the bar without breaking either cable is 550 N.

Explanation:

Given

Maximum tension in wire A ,

Maximum tension in wire B ,

Weight of bar ,

Length of wire , L=

Part A

Let the heaviest weight put on the bar without breaking either cable be W

Using Newton's Second law

=>

=>W = 550 N

Thus  the heaviest weight that can be put on the bar without breaking either cable is 550 N

The heaviest weight you can put on the bar without breaking either cable is 550 N

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

Given:

weight of the bar = w_b = 350 N

length of the bar = L_b = 1.50 m

maximum tension of cable A = T_A = 500.0 N

maximum tension of cable B = T_B = 400.0 N

Asked:

weight of a small object = w = ?

Solution:

We will use Newton's Law of Motion to solve this problem as follows:

Grade: High School

Subject: Physics

Chapter: Dynamics

total distance travelled = 60 miles

total time taken =1.5 hours

average speed = total distance / total time

60 / 1.5

= 40

therefore, average speed = 40 m/h

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