The specific heat of a 101 g block of material is to be determined. the block is placed in a 25 g copper calorimeter that also holds 60 g of water. the system is initially at 20°c. then 125 ml of water at 80°c are added to the calorimeter vessel. when thermal equilibrium is attained, the temperature of the water is 54°c. determine the specific heat of the block.

c = 0.329 cal/g.K

Explanation:

total Heat released  = mass x specific heat capacity of water x temperature change

= 125 x 1 x (80 - 54) = 3250 cal

Heat absorbed by material = mass x specific heat capacity of material x temperature change

= 101 x c x (54 - 20) = 3434*c cal

Heat absorbed by calorimeter = mass x specific heat capacity of Cu x temperature change

= 25 x 0.092 x (54 - 20) = 78.2 cal

Heat absorbed by water = mass x specific heat capacity of water x temperature change

= 60 x 1 x (54 - 20) = 2040 cal

Conservation of energy requires total heat absorbed = total heat released

3434*c+ 78.2 + 2040 = 3250

c = 0.329 cal/g.K

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