Consider an electrolytic cell at 298 k based on the following two half reactions hg2 2+ + 2e- æ 2 hg (l) 0.80 v fe3+ + e- æ fe 2+ 0.77 v under standard conditions. what will the potential of this cell be when the concentration of hg2 2+ has changed by 0.35 m? you can assume that the volumes of all solutions are exactly 1.0 l for this problem.

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explanation:

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less than one you can't create energy

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.