A21.6-kg cube made from aluminum is at its melting temperature of 660℃. if you were to add 8000 kj worth of energy as heat, what percent of the block melts? you might need the following: α = 23.0 ✕ 10-6 k-1 , β = 69.0 ✕ 10-6 k-1 , c = 900 j/kgk, lf = 3.98 ✕ 105 j/kg

The percentage of block melts is 93.1 %

Explanation:

Let the block melted be m₁

Given: LF = 3.98 * 10⁵ J/kg

Amount of heat added , Q = 8000 KJ  = 8×10⁶ J

Using:

Q = m₁×LF

8×10⁶ = m₁ * 3.98 * 10⁵

m₁ = 20.1 kg

So, the percentage of block melts , % = m₁/m * 100

% = 20.1 /21.6 * 100 = 93.1 %

The percentage of block melts is 93.1 %

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