In a certain cyclotron a proton moves in a circle of radius 0.670 m. the magnitude of the magnetic field is 1.30 t. (a) what is the oscillator frequency? (b) what is the kinetic energy of the proton?

a) The formula for a cyclotron's frequency:

f = (qB)/(2πm)

f is the frequency, q is the particle's charge, B is the magnetic field strength, and m is the particle's mass.

Given values:

q = 1.6×10⁻¹⁹C (proton charge)

B = 1.30T

m = 1.67×10⁻²⁷kg (proton mass)

Plug in these values and solve for f:

f = (1.6×10⁻¹⁹×1.30)/(2π×1.67×10⁻²⁷)

f = 1.98×10⁷Hz

b) The kinetic energy of a particle in the cyclotron is:

KE = 0.5q²B²r²/m

q is the particle's charge, B is the magnetic field strength, r is the radius of the particle's path, and m is the particle's mass.

Given values:

q = 1.6×10⁻¹⁹C (proton charge)

B = 1.30T

r = 0.670m

m = 1.67×10⁻²⁷kg (proton mass)

Plug in the values and solve for KE:

KE = (0.5)(1.6×10⁻¹⁹)²(1.30)²(0.670)²/1.67×10⁻²⁷

KE = 5.81×10⁻¹²J

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.

friction

explanation:

they us to move forward and backwards