Asimple pendulum consists of a ball connected to one end of a thin brass wire. the period of the pendulum is 2.51 s. the temperature rises by 142 c°, and the length of the wire increases. determine the change in the period of the heated pendulum.

The period of the heated pendulum is of T= 2.5124 seconds.

Explanation:

α= 18 * 10⁻⁶ 1/ºC

T1= 2.51 s

T2= ?

g= 9.8 m/s²

ΔTemp= 142ºC

L1= (T1/2π)² *g

L1= 1.563m

L2= α * L1 * ΔTemp + L1

L2= 1.567 m

T2= 2π * √(L2/g)

T2= 2.5124 sec

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.