A5.20 -kg ball is dropped from a height of 11.5 m above one end of a uniform bar that pivots at its center. the bar has mass 5.50 kg and is 6.40 m in length. at the other end of the bar sits another 6.00 how high will the other ball go after the collision? kg ball, unattached to the bar. the dropped ball sticks to the bar after the collision.

what was the acceleration of the 2 kg cart?

⇒ 16.0 cm/s2

what was the acceleration of the 4 kg cart?

⇒ 8.1 cm/s2

what was the acceleration of the 6 kg cart?

⇒ 5.3 cm/s2

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft