Acar moving 18.2 m/s starts to coast up a frictionless 10.0° hill. how far does it roll before coming to a stop (unit=m)

98.4 m

explanation:

let s = distance up the plane  

then by conservation of energy  

1/2m(18.3)^2 = mg s sin(10)  

(18.3)^2 = 2g s sin(10)  

s = (18.3)^2/2gsin(10)  

= 98.39564526  

= 98.4 m

c)as speed changes, wavelength and frequency change.

everything changes!

explanation:

v=uf/(u-f)

= 5.-10/(5+10) convex lens has negative focal length