Four point masses, each of mass 1.9 $kg$ are placed at the corners of a square of side 2.2 $m$. find the moment of inertia of this system about an axis that is perpendicular to the plane of the square and passes through one of the masses.

I = 36.78 kg m^{2}

Explanation:\

Given data:

side of square = 2.2 m

mass =1.9 kg

The moment of inertia i is the total sum of the moments of inertia of the 4 point masses  and it is given as

       =

I = 36.78 kg m^{2}

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