0.5000 kg of water at 35.00 degrees celsius is cooled, with the removal of 6.300 e4 j of heat. what is the final temperature of the water? specific heat capacity of water is 4186 j/(kg co).remember to identity all of your data, write the equation, and show your work.

Answer : The final temperature of the water is

Explanation :

Formula used :

where,

q = heat released =

m = mass of water = 0.5000 kg

c = specific heat of water =

= final temperature = ?

= initial temperature =

Now put all the given values in the above formula, we get:

Therefore, the final temperature of the water is

force tends to be low and long diustance masses are high

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer