A0.40-kg object is traveling to the right (in the positive direction) with a speed of 2.0 m/s. after a 0.20 s collision, the object is traveling to the left at 3.0 m/s. what is the magnitude of the impulse (in n-s) acting on the object? the answer must be positive. (never include units in the answer to a numerical question.)

vapour or gas assuming atmospheriv pressure

answerscientific theory;

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft