Adisc rotates at a constant angular speed. the turn around time (t) is 0.5 seconds.
a point x of the disc is located at a distance of 20 cm from the center.
a: calculate the speed of the disc
b: calculate the web speed of x
c: calculate the angular speed of the disc
d: calculate the midpoint angle over which the disc rotates in 4 seconds.
e: calculate the path that the point x travels in 4 seconds.
can someone solve this

Answershe should not have multiplied the sulfur atoms by the subscript 4

Let l be the vertical distance of pendulum when it makes 25.0 degree angle to verticalcos(25.0) = l / 1.20 ml = (1.20m)(cos 25.0)so the height, h, of the pendulum above the equilibrium position is h = 1.20m - (1.20m)(cos 25.0)ep,i + ek, i = ep, f = ek, fwhen pendulum held at 25.0 degrees, initial kinetic energy is 0 jwhen pendulum passes through equilibrium point, final potential energy is 0jep, i = ek fmgh = 1/2 m v^2gh = 1/2 m v^2v = √(2gh)v = √[2 * 9.81 m/s² * ( 1.20m - (1.20m)(cos 25.0) )]v = 1.5 m/s

Answer braking too hard