When adjusted for any changes in δh and δs with temperature, the standard free energy change δg∘t at 2400 k is equal to 1.22×105j/mol . calculate the equilibrium constant at 2400 k .

K=0.0022

Explanation:

ΔG° = 1.22×10⁵ J/mol

Temperature (T) = 2400 K

ΔG° = - RT ln K

where R is gas constant whose value is 8.314 J/Kmol

           K  is equilibrium constant

           ΔG° standard free energy

ln K =

K =  

K =

K= 0.0022

hence equilibrium constant value is K=0.0022

explanation:

newton's third law, for every action there is an equal and opposite reaction.