The frequency factor and activation energy for a chemical reaction are a = 4.23 x 10–12 cm3/(molecule·s) and ea = 12.9 kj/mol at 384.7 k, respectively. determine the rate constant for this reaction at 384.7 k.

Answer : The rate constant for this reaction at 384.7 K is,

Explanation :

The relation between frequency factor, rate constant and activation energy for a chemical reaction is,

where,

k = rate constant = ?

A = frequency factor =

Ea = activation energy = 12.9 kJ/mol

T = temperature = 384.7 K

Now put all the given values in this formula, we get:

Therefore, the rate constant for this reaction at 384.7 K is,

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explanation: