Two particles, one with charge -5.45 uc and one with charge 3.55 uc, are 4.34 cm apart. what is the magnitude of the force that one particle exerts on the other?

Force, F = 92.02 N

Explanation:

It is given that,

Charge 1,

Charge 2,

Distance between two charges, d = 4.35 cm = 0.0435 m

We need to find the magnitude of the force that one particle exerts on the other. It is given by :

F = -92.02 N

So, the force acting between two particles is 92.02 N. Hence, this is the required solution.

Explanation:

As we know that the force between two charge particles is given by

here we know that

now the distance between the two charges is

r = 4.34 cm

now from the formula of electrostatic force we will have

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dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.