The uncertainty in a proton's position is 0.015 nm. a) what is the minimum uncertainty δp in its momentum? b) what is the kinetic energy of a proton whose momentum is equal to this uncertainty (δp=p)? (unit: mev)

kg m/s

J

Explanation:

given data

uncertainty in proton position = 0.015 nm

according to Heisenberg's principle of uncertainty

Where h is plank constant = j-s

kg m/s

b) kinetic energy  of proton whose momentum

where m is mass is proton

J

the answer is a)

mark brainliest

get the total number of pieces of fruit and divide it by 4 to get the average. the result is the answer to the problem. 14 total number of fruits and there are 4 members. 14 divided by 4 is equals to 3.5.