Acharge q = 3 × 10-6 c of mass m = 2 × 10-6 kg, and speed v = 5 × 106 m/s enters a uniform magnetic field. the mass experiences an acceleration a = 3 × 104 m/s2. what is the minimum magnetic field that would produce such an acceleration?

Magnetic field, B = 0.004 mT

Explanation:

It is given that,

Charge,

Mass of charge particle,

Speed,

Acceleration,

We need to find the minimum magnetic field that would produce such an acceleration. So,

For minimum magnetic field,

B = 0.004 T

or

B = 4 mT

So, the magnetic field produce such an acceleration at 4 mT. Hence, this is the required solution.

note: the given question is incomplete.

complete question is given below.

which is an example of kinetic energy?

a. the energy stored in ethanol  

b. a hockey puck sliding across the ice  

c. a compressed spring  

d. a ball sitting at the top of a ramp

solution: the kinetic energy is the energy posses by the virtue of the motion of the object.

in the given options, a, c and d are the example of potential energy because it is the energy posses by the virtue of the rest of the object. but option b has the kinetic energy as the object is in motion.

hence, a hockey puck sliding across the ice   is the apex example of kinetic energy.

so, the option (b) a hockey puck sliding across the ice   is the correct option.