The current in a coil with a self-inductance of 1 mh is 2.8 a at t = 0, when the coil is shorted through a resistor. the total resistance of the coil plus the resistor is 11.0 capital omega. (a) find the current in the circuit after 0.5 ms.

Given:

L = 1 mH = H

total Resistance, R = 11

current at t = 0 s,

= 2.8 A

Formula used:

Solution:

Using the given formula:

current after t = 0.5 ms =

for the inductive circuit:

I =0.011 A

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

d) physical means can be used to separate the components of air.