2points
an athlete jumps with a speed of 4 m/s at an angle of 23º. how long does the
athlete stay in the air?
o a. 0.32 s
o b. 0.925
o c. 0.55 s
o d. 0.75 s

A. 0.32s

Explanation:

Lets find the initial velocity of the vertical component

Cos23=u/4

4cos23=1.6m/s

then time, t =2u/g

2×1.6/9.8

=0.32seconds

A. 0.32 s

Explanation:

The other answer did the math wrong but came up with the same answer. Anyway, you're supposed to use sin.

4sin(23) gives you 1.56 or 1.6

-1.56/-9.8 (negative because gravity is working against the direction of of the athlete as he goes into the air) = 0.159...

0.159*2 = 0.318

Round: 0.32

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.

a 2,000 calorie based diet.