Two 10-cm-diameter charged rings face each other, 25.0 cm apart. both rings are charged too + 50.0 nc . what is the electric field strength?

6773.54 V/m

Explanation:

Given data

Distance between two rings(x)=25cm

Charge on each ring(Q)= C

diameter of ring(d)=10 cm

Now Electric field strength at distance x from ring=

Where K=coulomb's constant==8.98\times 10^{9]

Now electric field strength at midpoint between two rings is zero

because one is pointing towards positive x direction and other in negative z direction.

but electric field strength at center of ring  due to other ring is given by

=

=

=6773.54 V/m

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )