An object of mass m = 20 kg moves with shm along the x-axis. at time t = 0 it is located at a distance of 4 m away from the origin which is located at x = 0, and has a velocity v = 15 m/s and acceleration, a = 10 m/s^2 which is directed towards the origin. find the position at any time. the amplitude, period and frequency of the oscillations. the force on the object when t = pie/10 seconds.

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

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