consider a shale-free, dry, sandstone core plug. by measurement, the following data are known: d=254 cm, l= 6.00 cm, and mass (dry)=548 g. 1 knowing that the grain density of most sandstone is about 2.65 gm/cu. cm, estimate the porosity of the core plug. 2. the plug is completely saturated with 145,000-ppm nacl brine whose specific gravity is 1.1 the mass of the saturated core plug is now 60.38 g. calculate the porosity of the plug. 3. estimate the end-to-end resistance ofthe saturated core plug inohm at 80 degree fahrenheit. use chevron's formula for f when required. 4. by actual measurement, the end-to-end resistance of the plug is 83.3 ohm. calculate the ro value of the plug. 5. some of the brine is removed from the core plug: i. e, the core is partially desaturated. its mass now is 56.03 g. calculate the water saturation. 6. for anexponent n of 3, what would be the end-to-end resistance of the core?

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

"induction" is the process of charging an object without touching it.hope my answer has you : )

We have no idea what the graph shows, or why it may be accurate,  because we can't see the graph.on a different subject, choice ' d ' is the only true statement among the choices.